S13-Words-for-the-Future-notebooks/dictionary-step-by-step.ipynb

Dictionary¶

In [1]:

d = dict()

In [2]:

d

Out[2]:

{}

In [3]:

d = { 'software' : 10 }

In [4]:

d

Out[4]:

{'software': 10}

In [5]:

d['software']

Out[5]:

10

In [6]:

d[10]

---------------------------------------------------------------------------
KeyError                                  Traceback (most recent call last)
<ipython-input-6-76a0c2738598> in <module>
----> 1 d[10]

KeyError: 10

In [7]:

d['language'] = 6

In [8]:

d

Out[8]:

{'software': 10, 'language': 6}

In [11]:

word = 'hello'
if word in d:
    print(f'{word} is in the dictionary')
else: 
    print(f'{word} is not in the dictionary')

hello is not in the dictionary

In [12]:

d.sort()

---------------------------------------------------------------------------
AttributeError                            Traceback (most recent call last)
<ipython-input-12-a6324fc0ae3a> in <module>
----> 1 d.sort()

AttributeError: 'dict' object has no attribute 'sort'

Sort a dictionary¶

In [19]:

list_of_keys = d.keys()

In [20]:

list_of_keys

Out[20]:

dict_keys(['software', 'language'])

In [26]:

keys = []
# key : value
for key, value in d.items():
    keys.append(key)

In [27]:

keys.sort()

In [28]:

keys

Out[28]:

['language', 'software']

In [32]:

for key in keys:
    print(f'{key} is here so many times:', d[key])

language is here so many times: 6
software is here so many times: 10

In [ ]:

In [ ]:

In [ ]: