from numpy import (logical_and, asarray, pi, zeros_like, piecewise, array, arctan2, tan, zeros, arange, floor) from numpy.core.umath import (sqrt, exp, greater, less, cos, add, sin, less_equal, greater_equal) # From splinemodule.c from .spline import cspline2d, sepfir2d from scipy.special import comb from scipy._lib._util import float_factorial __all__ = ['spline_filter', 'bspline', 'gauss_spline', 'cubic', 'quadratic', 'cspline1d', 'qspline1d', 'cspline1d_eval', 'qspline1d_eval'] def spline_filter(Iin, lmbda=5.0): """Smoothing spline (cubic) filtering of a rank-2 array. Filter an input data set, `Iin`, using a (cubic) smoothing spline of fall-off `lmbda`. Parameters ---------- Iin : array like input data set lmbda : float, optional spline smooghing fall-off value, default is `5.0`. Returns ------- res : ndarray filterd input data Examples -------- We can filter an multi dimentional signal (ex: 2D image) using cubic B-spline filter: >>> from scipy.signal import spline_filter >>> import matplotlib.pyplot as plt >>> orig_img = np.eye(20) # create an image >>> orig_img[10, :] = 1.0 >>> sp_filter = spline_filter(orig_img, lmbda=0.1) >>> f, ax = plt.subplots(1, 2, sharex=True) >>> for ind, data in enumerate([[orig_img, "original image"], ... [sp_filter, "spline filter"]]): ... ax[ind].imshow(data[0], cmap='gray_r') ... ax[ind].set_title(data[1]) >>> plt.tight_layout() >>> plt.show() """ intype = Iin.dtype.char hcol = array([1.0, 4.0, 1.0], 'f') / 6.0 if intype in ['F', 'D']: Iin = Iin.astype('F') ckr = cspline2d(Iin.real, lmbda) cki = cspline2d(Iin.imag, lmbda) outr = sepfir2d(ckr, hcol, hcol) outi = sepfir2d(cki, hcol, hcol) out = (outr + 1j * outi).astype(intype) elif intype in ['f', 'd']: ckr = cspline2d(Iin, lmbda) out = sepfir2d(ckr, hcol, hcol) out = out.astype(intype) else: raise TypeError("Invalid data type for Iin") return out _splinefunc_cache = {} def _bspline_piecefunctions(order): """Returns the function defined over the left-side pieces for a bspline of a given order. The 0th piece is the first one less than 0. The last piece is a function identical to 0 (returned as the constant 0). (There are order//2 + 2 total pieces). Also returns the condition functions that when evaluated return boolean arrays for use with `numpy.piecewise`. """ try: return _splinefunc_cache[order] except KeyError: pass def condfuncgen(num, val1, val2): if num == 0: return lambda x: logical_and(less_equal(x, val1), greater_equal(x, val2)) elif num == 2: return lambda x: less_equal(x, val2) else: return lambda x: logical_and(less(x, val1), greater_equal(x, val2)) last = order // 2 + 2 if order % 2: startbound = -1.0 else: startbound = -0.5 condfuncs = [condfuncgen(0, 0, startbound)] bound = startbound for num in range(1, last - 1): condfuncs.append(condfuncgen(1, bound, bound - 1)) bound = bound - 1 condfuncs.append(condfuncgen(2, 0, -(order + 1) / 2.0)) # final value of bound is used in piecefuncgen below # the functions to evaluate are taken from the left-hand side # in the general expression derived from the central difference # operator (because they involve fewer terms). fval = float_factorial(order) def piecefuncgen(num): Mk = order // 2 - num if (Mk < 0): return 0 # final function is 0 coeffs = [(1 - 2 * (k % 2)) * float(comb(order + 1, k, exact=1)) / fval for k in range(Mk + 1)] shifts = [-bound - k for k in range(Mk + 1)] def thefunc(x): res = 0.0 for k in range(Mk + 1): res += coeffs[k] * (x + shifts[k]) ** order return res return thefunc funclist = [piecefuncgen(k) for k in range(last)] _splinefunc_cache[order] = (funclist, condfuncs) return funclist, condfuncs def bspline(x, n): """B-spline basis function of order n. Parameters ---------- x : array like a knot vector n : int The order of the spline. Must be non-negative, i.e., n >= 0 Returns ------- res : ndarray B-spline basis function values See Also -------- cubic : A cubic B-spline. quadratic : A quadratic B-spline. Notes ----- Uses numpy.piecewise and automatic function-generator. Examples -------- We can calculate B-Spline basis function of several orders: >>> from scipy.signal import bspline, cubic, quadratic >>> bspline(0.0, 1) 1 >>> knots = [-1.0, 0.0, -1.0] >>> bspline(knots, 2) array([0.125, 0.75, 0.125]) >>> np.array_equal(bspline(knots, 2), quadratic(knots)) True >>> np.array_equal(bspline(knots, 3), cubic(knots)) True """ ax = -abs(asarray(x)) # number of pieces on the left-side is (n+1)/2 funclist, condfuncs = _bspline_piecefunctions(n) condlist = [func(ax) for func in condfuncs] return piecewise(ax, condlist, funclist) def gauss_spline(x, n): r"""Gaussian approximation to B-spline basis function of order n. Parameters ---------- x : array a knot vector n : int The order of the spline. Must be non-negative, i.e., n >= 0 Returns ------- res : ndarray B-spline basis function values approximated by a zero-mean Gaussian function. Notes ----- The B-spline basis function can be approximated well by a zero-mean Gaussian function with standard-deviation equal to :math:`\sigma=(n+1)/12` for large `n` : .. math:: \frac{1}{\sqrt {2\pi\sigma^2}}exp(-\frac{x^2}{2\sigma}) References ---------- .. [1] Bouma H., Vilanova A., Bescos J.O., ter Haar Romeny B.M., Gerritsen F.A. (2007) Fast and Accurate Gaussian Derivatives Based on B-Splines. In: Sgallari F., Murli A., Paragios N. (eds) Scale Space and Variational Methods in Computer Vision. SSVM 2007. Lecture Notes in Computer Science, vol 4485. Springer, Berlin, Heidelberg .. [2] http://folk.uio.no/inf3330/scripting/doc/python/SciPy/tutorial/old/node24.html Examples -------- We can calculate B-Spline basis functions approximated by a gaussian distribution: >>> from scipy.signal import gauss_spline, bspline >>> knots = np.array([-1.0, 0.0, -1.0]) >>> gauss_spline(knots, 3) array([0.15418033, 0.6909883, 0.15418033]) # may vary >>> bspline(knots, 3) array([0.16666667, 0.66666667, 0.16666667]) # may vary """ x = asarray(x) signsq = (n + 1) / 12.0 return 1 / sqrt(2 * pi * signsq) * exp(-x ** 2 / 2 / signsq) def cubic(x): """A cubic B-spline. This is a special case of `bspline`, and equivalent to ``bspline(x, 3)``. Parameters ---------- x : array like a knot vector Returns ------- res : ndarray Cubic B-spline basis function values See Also -------- bspline : B-spline basis function of order n quadratic : A quadratic B-spline. Examples -------- We can calculate B-Spline basis function of several orders: >>> from scipy.signal import bspline, cubic, quadratic >>> bspline(0.0, 1) 1 >>> knots = [-1.0, 0.0, -1.0] >>> bspline(knots, 2) array([0.125, 0.75, 0.125]) >>> np.array_equal(bspline(knots, 2), quadratic(knots)) True >>> np.array_equal(bspline(knots, 3), cubic(knots)) True """ ax = abs(asarray(x)) res = zeros_like(ax) cond1 = less(ax, 1) if cond1.any(): ax1 = ax[cond1] res[cond1] = 2.0 / 3 - 1.0 / 2 * ax1 ** 2 * (2 - ax1) cond2 = ~cond1 & less(ax, 2) if cond2.any(): ax2 = ax[cond2] res[cond2] = 1.0 / 6 * (2 - ax2) ** 3 return res def quadratic(x): """A quadratic B-spline. This is a special case of `bspline`, and equivalent to ``bspline(x, 2)``. Parameters ---------- x : array like a knot vector Returns ------- res : ndarray Quadratic B-spline basis function values See Also -------- bspline : B-spline basis function of order n cubic : A cubic B-spline. Examples -------- We can calculate B-Spline basis function of several orders: >>> from scipy.signal import bspline, cubic, quadratic >>> bspline(0.0, 1) 1 >>> knots = [-1.0, 0.0, -1.0] >>> bspline(knots, 2) array([0.125, 0.75, 0.125]) >>> np.array_equal(bspline(knots, 2), quadratic(knots)) True >>> np.array_equal(bspline(knots, 3), cubic(knots)) True """ ax = abs(asarray(x)) res = zeros_like(ax) cond1 = less(ax, 0.5) if cond1.any(): ax1 = ax[cond1] res[cond1] = 0.75 - ax1 ** 2 cond2 = ~cond1 & less(ax, 1.5) if cond2.any(): ax2 = ax[cond2] res[cond2] = (ax2 - 1.5) ** 2 / 2.0 return res def _coeff_smooth(lam): xi = 1 - 96 * lam + 24 * lam * sqrt(3 + 144 * lam) omeg = arctan2(sqrt(144 * lam - 1), sqrt(xi)) rho = (24 * lam - 1 - sqrt(xi)) / (24 * lam) rho = rho * sqrt((48 * lam + 24 * lam * sqrt(3 + 144 * lam)) / xi) return rho, omeg def _hc(k, cs, rho, omega): return (cs / sin(omega) * (rho ** k) * sin(omega * (k + 1)) * greater(k, -1)) def _hs(k, cs, rho, omega): c0 = (cs * cs * (1 + rho * rho) / (1 - rho * rho) / (1 - 2 * rho * rho * cos(2 * omega) + rho ** 4)) gamma = (1 - rho * rho) / (1 + rho * rho) / tan(omega) ak = abs(k) return c0 * rho ** ak * (cos(omega * ak) + gamma * sin(omega * ak)) def _cubic_smooth_coeff(signal, lamb): rho, omega = _coeff_smooth(lamb) cs = 1 - 2 * rho * cos(omega) + rho * rho K = len(signal) yp = zeros((K,), signal.dtype.char) k = arange(K) yp[0] = (_hc(0, cs, rho, omega) * signal[0] + add.reduce(_hc(k + 1, cs, rho, omega) * signal)) yp[1] = (_hc(0, cs, rho, omega) * signal[0] + _hc(1, cs, rho, omega) * signal[1] + add.reduce(_hc(k + 2, cs, rho, omega) * signal)) for n in range(2, K): yp[n] = (cs * signal[n] + 2 * rho * cos(omega) * yp[n - 1] - rho * rho * yp[n - 2]) y = zeros((K,), signal.dtype.char) y[K - 1] = add.reduce((_hs(k, cs, rho, omega) + _hs(k + 1, cs, rho, omega)) * signal[::-1]) y[K - 2] = add.reduce((_hs(k - 1, cs, rho, omega) + _hs(k + 2, cs, rho, omega)) * signal[::-1]) for n in range(K - 3, -1, -1): y[n] = (cs * yp[n] + 2 * rho * cos(omega) * y[n + 1] - rho * rho * y[n + 2]) return y def _cubic_coeff(signal): zi = -2 + sqrt(3) K = len(signal) yplus = zeros((K,), signal.dtype.char) powers = zi ** arange(K) yplus[0] = signal[0] + zi * add.reduce(powers * signal) for k in range(1, K): yplus[k] = signal[k] + zi * yplus[k - 1] output = zeros((K,), signal.dtype) output[K - 1] = zi / (zi - 1) * yplus[K - 1] for k in range(K - 2, -1, -1): output[k] = zi * (output[k + 1] - yplus[k]) return output * 6.0 def _quadratic_coeff(signal): zi = -3 + 2 * sqrt(2.0) K = len(signal) yplus = zeros((K,), signal.dtype.char) powers = zi ** arange(K) yplus[0] = signal[0] + zi * add.reduce(powers * signal) for k in range(1, K): yplus[k] = signal[k] + zi * yplus[k - 1] output = zeros((K,), signal.dtype.char) output[K - 1] = zi / (zi - 1) * yplus[K - 1] for k in range(K - 2, -1, -1): output[k] = zi * (output[k + 1] - yplus[k]) return output * 8.0 def cspline1d(signal, lamb=0.0): """ Compute cubic spline coefficients for rank-1 array. Find the cubic spline coefficients for a 1-D signal assuming mirror-symmetric boundary conditions. To obtain the signal back from the spline representation mirror-symmetric-convolve these coefficients with a length 3 FIR window [1.0, 4.0, 1.0]/ 6.0 . Parameters ---------- signal : ndarray A rank-1 array representing samples of a signal. lamb : float, optional Smoothing coefficient, default is 0.0. Returns ------- c : ndarray Cubic spline coefficients. See Also -------- cspline1d_eval : Evaluate a cubic spline at the new set of points. Examples -------- We can filter a signal to reduce and smooth out high-frequency noise with a cubic spline: >>> import matplotlib.pyplot as plt >>> from scipy.signal import cspline1d, cspline1d_eval >>> sig = np.repeat([0., 1., 0.], 100) >>> sig += np.random.randn(len(sig))*0.05 # add noise >>> time = np.linspace(0, len(sig)) >>> filtered = cspline1d_eval(cspline1d(sig), time) >>> plt.plot(sig, label="signal") >>> plt.plot(time, filtered, label="filtered") >>> plt.legend() >>> plt.show() """ if lamb != 0.0: return _cubic_smooth_coeff(signal, lamb) else: return _cubic_coeff(signal) def qspline1d(signal, lamb=0.0): """Compute quadratic spline coefficients for rank-1 array. Parameters ---------- signal : ndarray A rank-1 array representing samples of a signal. lamb : float, optional Smoothing coefficient (must be zero for now). Returns ------- c : ndarray Quadratic spline coefficients. See Also -------- qspline1d_eval : Evaluate a quadratic spline at the new set of points. Notes ----- Find the quadratic spline coefficients for a 1-D signal assuming mirror-symmetric boundary conditions. To obtain the signal back from the spline representation mirror-symmetric-convolve these coefficients with a length 3 FIR window [1.0, 6.0, 1.0]/ 8.0 . Examples -------- We can filter a signal to reduce and smooth out high-frequency noise with a quadratic spline: >>> import matplotlib.pyplot as plt >>> from scipy.signal import qspline1d, qspline1d_eval >>> sig = np.repeat([0., 1., 0.], 100) >>> sig += np.random.randn(len(sig))*0.05 # add noise >>> time = np.linspace(0, len(sig)) >>> filtered = qspline1d_eval(qspline1d(sig), time) >>> plt.plot(sig, label="signal") >>> plt.plot(time, filtered, label="filtered") >>> plt.legend() >>> plt.show() """ if lamb != 0.0: raise ValueError("Smoothing quadratic splines not supported yet.") else: return _quadratic_coeff(signal) def cspline1d_eval(cj, newx, dx=1.0, x0=0): """Evaluate a cubic spline at the new set of points. `dx` is the old sample-spacing while `x0` was the old origin. In other-words the old-sample points (knot-points) for which the `cj` represent spline coefficients were at equally-spaced points of: oldx = x0 + j*dx j=0...N-1, with N=len(cj) Edges are handled using mirror-symmetric boundary conditions. Parameters ---------- cj : ndarray cublic spline coefficients newx : ndarray New set of points. dx : float, optional Old sample-spacing, the default value is 1.0. x0 : int, optional Old origin, the default value is 0. Returns ------- res : ndarray Evaluated a cubic spline points. See Also -------- cspline1d : Compute cubic spline coefficients for rank-1 array. Examples -------- We can filter a signal to reduce and smooth out high-frequency noise with a cubic spline: >>> import matplotlib.pyplot as plt >>> from scipy.signal import cspline1d, cspline1d_eval >>> sig = np.repeat([0., 1., 0.], 100) >>> sig += np.random.randn(len(sig))*0.05 # add noise >>> time = np.linspace(0, len(sig)) >>> filtered = cspline1d_eval(cspline1d(sig), time) >>> plt.plot(sig, label="signal") >>> plt.plot(time, filtered, label="filtered") >>> plt.legend() >>> plt.show() """ newx = (asarray(newx) - x0) / float(dx) res = zeros_like(newx, dtype=cj.dtype) if res.size == 0: return res N = len(cj) cond1 = newx < 0 cond2 = newx > (N - 1) cond3 = ~(cond1 | cond2) # handle general mirror-symmetry res[cond1] = cspline1d_eval(cj, -newx[cond1]) res[cond2] = cspline1d_eval(cj, 2 * (N - 1) - newx[cond2]) newx = newx[cond3] if newx.size == 0: return res result = zeros_like(newx, dtype=cj.dtype) jlower = floor(newx - 2).astype(int) + 1 for i in range(4): thisj = jlower + i indj = thisj.clip(0, N - 1) # handle edge cases result += cj[indj] * cubic(newx - thisj) res[cond3] = result return res def qspline1d_eval(cj, newx, dx=1.0, x0=0): """Evaluate a quadratic spline at the new set of points. Parameters ---------- cj : ndarray Quadratic spline coefficients newx : ndarray New set of points. dx : float, optional Old sample-spacing, the default value is 1.0. x0 : int, optional Old origin, the default value is 0. Returns ------- res : ndarray Evaluated a quadratic spline points. See Also -------- qspline1d : Compute quadratic spline coefficients for rank-1 array. Notes ----- `dx` is the old sample-spacing while `x0` was the old origin. In other-words the old-sample points (knot-points) for which the `cj` represent spline coefficients were at equally-spaced points of:: oldx = x0 + j*dx j=0...N-1, with N=len(cj) Edges are handled using mirror-symmetric boundary conditions. Examples -------- We can filter a signal to reduce and smooth out high-frequency noise with a quadratic spline: >>> import matplotlib.pyplot as plt >>> from scipy.signal import qspline1d, qspline1d_eval >>> sig = np.repeat([0., 1., 0.], 100) >>> sig += np.random.randn(len(sig))*0.05 # add noise >>> time = np.linspace(0, len(sig)) >>> filtered = qspline1d_eval(qspline1d(sig), time) >>> plt.plot(sig, label="signal") >>> plt.plot(time, filtered, label="filtered") >>> plt.legend() >>> plt.show() """ newx = (asarray(newx) - x0) / dx res = zeros_like(newx) if res.size == 0: return res N = len(cj) cond1 = newx < 0 cond2 = newx > (N - 1) cond3 = ~(cond1 | cond2) # handle general mirror-symmetry res[cond1] = qspline1d_eval(cj, -newx[cond1]) res[cond2] = qspline1d_eval(cj, 2 * (N - 1) - newx[cond2]) newx = newx[cond3] if newx.size == 0: return res result = zeros_like(newx) jlower = floor(newx - 1.5).astype(int) + 1 for i in range(3): thisj = jlower + i indj = thisj.clip(0, N - 1) # handle edge cases result += cj[indj] * quadratic(newx - thisj) res[cond3] = result return res