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51 lines
2.0 KiB
Python
51 lines
2.0 KiB
Python
5 years ago
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from __future__ import print_function
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from __future__ import unicode_literals
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from builtins import str, bytes, dict, int
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from builtins import range
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import os
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import sys
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sys.path.insert(0, os.path.join(os.path.dirname(__file__), "..", ".."))
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from pattern.web import Google, plaintext
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from pattern.web import SEARCH
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# The pattern.web module has a SearchEngine class,
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# with a SearchEngine.search() method that yields a list of Result objects.
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# Each Result has url, title, text, language, author and date and properties.
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# Subclasses of SearchEngine include:
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# Google, Bing, Yahoo, Twitter, Facebook, Wikipedia, Wiktionary, Flickr, ...
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# This example retrieves results from Google based on a given query.
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# The Google search engine can handle SEARCH type searches.
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# Other search engines may also handle IMAGE, NEWS, ...
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# Google's "Custom Search API" is a paid service.
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# The pattern.web module uses a test account by default,
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# with a 100 free queries per day shared by all Pattern users.
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# If this limit is exceeded, SearchEngineLimitError is raised.
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# You should obtain your own license key at:
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# https://code.google.com/apis/console/
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# Activate "Custom Search API" under "Services" and get the key under "API Access".
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# Then use Google(license=[YOUR_KEY]).search().
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# This will give you 100 personal free queries, or 5$ per 1000 queries.
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engine = Google(license=None, language="en")
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# Veale & Hao's method for finding similes using wildcards (*):
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# http://afflatus.ucd.ie/Papers/LearningFigurative_CogSci07.pdf
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# This will match results such as:
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# - "as light as a feather",
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# - "as cute as a cupcake",
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# - "as drunk as a lord",
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# - "as snug as a bug", etc.
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q = "as * as a *"
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# Google is very fast but you can only get up to 100 (10x10) results per query.
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for i in range(1, 2):
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for result in engine.search(q, start=i, count=10, type=SEARCH, cached=True):
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print(plaintext(result.text)) # plaintext() removes all HTML formatting.
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print(result.url)
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print(result.date)
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print("")
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