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157 lines
5.2 KiB
Python
157 lines
5.2 KiB
Python
6 years ago
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"""
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=============================
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Byteswapping and byte order
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=============================
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Introduction to byte ordering and ndarrays
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==========================================
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The ``ndarray`` is an object that provide a python array interface to data
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in memory.
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It often happens that the memory that you want to view with an array is
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not of the same byte ordering as the computer on which you are running
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Python.
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For example, I might be working on a computer with a little-endian CPU -
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such as an Intel Pentium, but I have loaded some data from a file
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written by a computer that is big-endian. Let's say I have loaded 4
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bytes from a file written by a Sun (big-endian) computer. I know that
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these 4 bytes represent two 16-bit integers. On a big-endian machine, a
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two-byte integer is stored with the Most Significant Byte (MSB) first,
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and then the Least Significant Byte (LSB). Thus the bytes are, in memory order:
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#. MSB integer 1
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#. LSB integer 1
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#. MSB integer 2
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#. LSB integer 2
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Let's say the two integers were in fact 1 and 770. Because 770 = 256 *
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3 + 2, the 4 bytes in memory would contain respectively: 0, 1, 3, 2.
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The bytes I have loaded from the file would have these contents:
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>>> big_end_str = chr(0) + chr(1) + chr(3) + chr(2)
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>>> big_end_str
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'\\x00\\x01\\x03\\x02'
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We might want to use an ``ndarray`` to access these integers. In that
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case, we can create an array around this memory, and tell numpy that
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there are two integers, and that they are 16 bit and big-endian:
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>>> import numpy as np
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>>> big_end_arr = np.ndarray(shape=(2,),dtype='>i2', buffer=big_end_str)
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>>> big_end_arr[0]
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1
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>>> big_end_arr[1]
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770
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Note the array ``dtype`` above of ``>i2``. The ``>`` means 'big-endian'
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(``<`` is little-endian) and ``i2`` means 'signed 2-byte integer'. For
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example, if our data represented a single unsigned 4-byte little-endian
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integer, the dtype string would be ``<u4``.
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In fact, why don't we try that?
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>>> little_end_u4 = np.ndarray(shape=(1,),dtype='<u4', buffer=big_end_str)
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>>> little_end_u4[0] == 1 * 256**1 + 3 * 256**2 + 2 * 256**3
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True
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Returning to our ``big_end_arr`` - in this case our underlying data is
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big-endian (data endianness) and we've set the dtype to match (the dtype
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is also big-endian). However, sometimes you need to flip these around.
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.. warning::
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Scalars currently do not include byte order information, so extracting
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a scalar from an array will return an integer in native byte order.
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Hence:
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>>> big_end_arr[0].dtype.byteorder == little_end_u4[0].dtype.byteorder
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True
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Changing byte ordering
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======================
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As you can imagine from the introduction, there are two ways you can
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affect the relationship between the byte ordering of the array and the
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underlying memory it is looking at:
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* Change the byte-ordering information in the array dtype so that it
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interprets the underlying data as being in a different byte order.
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This is the role of ``arr.newbyteorder()``
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* Change the byte-ordering of the underlying data, leaving the dtype
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interpretation as it was. This is what ``arr.byteswap()`` does.
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The common situations in which you need to change byte ordering are:
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#. Your data and dtype endianness don't match, and you want to change
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the dtype so that it matches the data.
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#. Your data and dtype endianness don't match, and you want to swap the
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data so that they match the dtype
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#. Your data and dtype endianness match, but you want the data swapped
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and the dtype to reflect this
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Data and dtype endianness don't match, change dtype to match data
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-----------------------------------------------------------------
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We make something where they don't match:
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>>> wrong_end_dtype_arr = np.ndarray(shape=(2,),dtype='<i2', buffer=big_end_str)
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>>> wrong_end_dtype_arr[0]
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256
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The obvious fix for this situation is to change the dtype so it gives
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the correct endianness:
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>>> fixed_end_dtype_arr = wrong_end_dtype_arr.newbyteorder()
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>>> fixed_end_dtype_arr[0]
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1
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Note the array has not changed in memory:
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>>> fixed_end_dtype_arr.tobytes() == big_end_str
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True
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Data and type endianness don't match, change data to match dtype
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----------------------------------------------------------------
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You might want to do this if you need the data in memory to be a certain
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ordering. For example you might be writing the memory out to a file
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that needs a certain byte ordering.
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>>> fixed_end_mem_arr = wrong_end_dtype_arr.byteswap()
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>>> fixed_end_mem_arr[0]
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1
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Now the array *has* changed in memory:
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>>> fixed_end_mem_arr.tobytes() == big_end_str
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False
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Data and dtype endianness match, swap data and dtype
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----------------------------------------------------
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You may have a correctly specified array dtype, but you need the array
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to have the opposite byte order in memory, and you want the dtype to
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match so the array values make sense. In this case you just do both of
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the previous operations:
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>>> swapped_end_arr = big_end_arr.byteswap().newbyteorder()
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>>> swapped_end_arr[0]
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1
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>>> swapped_end_arr.tobytes() == big_end_str
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False
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An easier way of casting the data to a specific dtype and byte ordering
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can be achieved with the ndarray astype method:
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>>> swapped_end_arr = big_end_arr.astype('<i2')
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>>> swapped_end_arr[0]
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1
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>>> swapped_end_arr.tobytes() == big_end_str
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False
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"""
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from __future__ import division, absolute_import, print_function
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